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Convergence considerations

All the three previous methods have a linear convergence, since at each iteration the ratio between the interval containing $ \mathbf{x}^\star$ and the new smaller interval is:

$\displaystyle 0 \leq \frac{I_{k+1}}{I_k} \leq 1.$    

The asymptotic convergence rate is defined as

$\displaystyle \lim_{k\rightarrow\infty}\frac{I_{k+1}}{I_k}.$    

For the dicotomic search, since $ 2I_{k+1} = I_k + \epsilon$, taking $ \epsilon = 0$ we have

$\displaystyle \lim_{k\rightarrow\infty}\frac{I_{k+1}}{I_k} = \frac{1}{2}.$    

For the Fibonacci search, first we must write the generic number of the Fibonacci sequence in a closed form:

$\displaystyle f_k = \frac{1}{\sqrt{5}}\biggl[\left(\frac{1+\sqrt{5}}{2}\right)^{k+1}- \left(\frac{1-\sqrt{5}}{2}\right)^{k+1}\biggr].$    

then it can be proved that, taking $ \epsilon = 0$:

$\displaystyle \lim_{k\rightarrow\infty}\frac{I_{k+1}}{I_k} = \lim_{k\rightarrow\infty}\frac{f_{k+1}}{f_k} = \frac{\sqrt{5}-1}{2}$    

For the golden section search, as previously said $ \frac{I_{k+1}}{I_k} = \lambda$, so

$\displaystyle \lim_{k\rightarrow\infty}\frac{I_{k+1}}{I_k} = \lambda = \frac{\sqrt{5}-1}{2}.$    

Thus the convergence rate of the Fibonacci and the golden-section search are identical.


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Next: Parabolic interpolation Up: The section search Previous: The golden section search   Contents
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